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Sed print matching lines

WebIn case you are trying to output only the matching portion BETWEEN two known strings, try echo "aSomethingYouWantb" sed -En 's/a (.*)b/\1/p' – luckman212 Oct 17, 2024 at 0:59 … WebThe common "solution" out there is to use search and replace and match the whole line: sed -n 's/.*\ ( [0-9]*%\).*/Battery: \1/p' Now the .* are too greedy and the \1 is only the %. Furthermore I don't want to match more than I need to. regex sed Share Improve this question Follow edited Mar 19, 2014 at 14:45 Oliver Salzburg 85.6k 62 259 306

how to grep and print the next N lines after the hit?

WebThe common "solution" out there is to use search and replace and match the whole line: sed -n 's/.*\ ( [0-9]*%\).*/Battery: \1/p' Now the .* are too greedy and the \1 is only the %. … Websed, a stream editor, To print only the lines you match, use sed -n to supress all lines printing and then put p in command to print the matched lines, such as sed -nr 's/.* ( [0-9]).*/\1/p' The ‘p’ command is preceded by a ‘2’. The number ‘2’ refers to line number two. You can tell sed to perform prints only on a particular line or lines. centre of italian studies https://xtreme-watersport.com

Sed to print only first pattern match of the line

WebIt's possible to change this using the --only-matching flag to show only the part of a line that matches your pattern (at least it is on GNU grep, I'm unsure about others). – Max Barraclough Jul 20, 2024 at 9:35 -w only works for whole word matches. e.g., for foobar, grep -w 'foo' ... will not match – Nick Bull Aug 3, 2024 at 11:14 Add a comment 1 Web13 Aug 2012 · Let us consider a sample file as below. The requirement is to print 2 lines before the pattern 'Linux': $ cat file Unix AIX Solaris Linux SCO. 1. grep will do it for you if your grep is a GNU grep. $ grep -B2 Linux file AIX Solaris Linux. The option '-B' will give n lines before the pattern. Hence '-B2 Linux' gives 2 lines before the pattern ... buy men\u0027s kid leather slippers

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Sed print matching lines

sed script to print n lines after the last occurence of a match

Web9 Apr 2024 · sed -E 's/ (s [0-9]+\.p:).*\sABC\s*=\s* (\w+),.*/\1 \2/g' Here (s [0-9]+\.p:).*\sABC\s*=\s* (\w+).* matches your input line, and replaces it with capturing of group number 1 and 2, separated by space. CAUTION: if you input string contains two blocks like ABC = something, ABC = something_entirely_else - second value will be used. Here I … Web27 Dec 2016 · Use one of the following commands to find and print all the lines of a file, that match multiple patterns. Using grep command (exact order): $ grep -E 'PATTERN1.*PATTERN2' FILE Using grep command (any order): $ grep -E 'PATTERN1.*PATTERN2 PATTERN2.*PATTERN1' FILE $ grep 'PATTERN1' FILE grep …

Sed print matching lines

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Web10 May 2024 · This is basically Glenn's solution, but implemented with Bash, Grep, and sed. grep -n match file while IFS=: read nr _; do sed -ns "$ ( (nr-5))p; $ ( (nr))p; $ ( (nr+5))p" file done Note that line numbers less than 1 will make sed error, and line numbers greater than the number of lines in the file will make it print nothing. Web16 Jun 2011 · Print N lines before and after matching lines. Using -C n option you can print N lines before and after matching lines. If you have GNU grep, it's the -A / --after-context option. Otherwise, you can do it with awk. awk '/regex/ {p=2} p > 0 {print $0; p--}' filename - works, yours not. Use the -A argument to grep to specify how many lines beyond ...

WebSed examples; Find and replace. Find and replace any match anywhere in the file; Find and replace on lines containing pattern; Find and replace the first match Web31 Jul 2014 · Print matching line and following lines to end of file >sed.exe -n -e "/needle/,$p" haystack.txt needle want 1 want 2 Print start of file up to BUT NOT including matching …

Web7 Nov 2012 · 1 Change your sed command as follows: sed -n "\:$var: {n;p;}" Two points: The best you could have hoped for with your version is to search for “ $var ”. To search for “ /somePath/to/my/home ”, you must replace your single quotes ( ') with double quotes ( ") to allow “ $var ” to be replaced by “ /somePath/to/my/home ”. Web30 rows · 19 Oct 2012 · In this example print or show any matching lines from /etc/passwd file: sed -n '/root/p' / ...

Web22 Mar 2011 · Using sed/awk to print lines with matching pattern OR another matching pattern. I need to print lines in a file matching a pattern OR a different pattern using awk or …

Web7 Nov 2012 · using sed to print next line after match. I came across various examples on printing next line after a match, that use awk and sed. I'm using it in my code and it works … centre of life spaceWeb14 Sep 2024 · I use sed a lot to track logs that begin with lines that matches a certain pattern. I use this command: In the code, I simply prepend log lines with identifiers so that … centre of light hopemanWeb1 Oct 2008 · Sed command to print matching lines and 2 lines above.. Programming This forum is for all programming questions. The question does not have to be directly related to Linux and any language is fair game. Notices Welcome to LinuxQuestions.org, a friendly and active Linux Community. You are currently viewing LQ as a guest. centre of interest photographyWeb17 May 2012 · To print only the line following the pattern without the line matching the pattern: $ sed -n '/Linux/ {n;p}' file Solaris The n command reads the next line into the pattern space thereby overwriting the current line. On printing the pattern space using the p command, we get the next line printed. 6. Same using awk: centre of management ipbWeb26 Apr 2012 · Sed works line oriented. If you like to replace one (the first) foo with bar, above command is okay. To replace all, you need 'g' for globally. sed 's/foo/bar/g' Other ways to … buy men\u0027s leather jacketsWeb14 Sep 2009 · Linux Sed command allows you to print only specific lines based on the line number or pattern matches. “p” is a command for printing the data from the pattern buffer. To suppress automatic printing of pattern space use -n command with sed. sed -n option will not print anything, unless an explicit request to print is found. Syntax: # sed -n ... centre of maritime excellence sdn bhdWebExample #. $ cat ip.txt address range substitution pattern sample. Range specified is inclusive of those line numbers. $ sed -n '2,4p' ip.txt range substitution pattern. $ can be used to specify last line. Space can be used between address and command for clarity. $ sed -n '3,$ s/ [aeiou]//gp' ip.txt sbstttn pttrn smpl. centre of india city